The top-ranked player Aryna Sabalenka has been voted the Women's Tennis Association player of the year for a second successive year.
The 27-year-old captured four titles – the highest tally on the circuit – which included successfully defending the US Open in September against Amanda Anisimova to secure her fourth Grand Slam singles championship.
Over the course of the tour, Sabalenka played in a tour-best nine championship matches, with defeats coming against Madison Keys in the Australian Open final at the start of the year and Coco Gauff in the French Open final.
The Belarusian also claimed victory at the Brisbane International in January, the Miami Open during the spring, and the Madrid Open as the clay season progressed. She remained the whole season as the world number one, finishing 2025 on top of the rankings for a second straight year.
This past summer, she became the first player to top 12,000 WTA ranking points since Serena Williams in 2015.
Sabalenka concluded the competitive year with a 63-12 win-loss record, and earned a historic eleven million pounds in earnings.
She garnered almost eighty percent of the votes cast by global tennis journalists.
On 28 December, she is poised to compete against 2022 Wimbledon runner-up Nick Kyrgios in a high-profile mixed-gender exhibition match with the aim of "raise women's tennis to a new level".
Last week, Carlos Alcaraz took home three honours in the Association of Tennis Professionals (ATP) Awards, which included the year-end number one award, while Jannik Sinner was chosen as the fan favorite for a third consecutive time.
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